示例
Show that `Set#intersect?` does not return a boolean for invalid scalar input.
sha256:5c69231633e7101fea59bbb26a50ac658769097fd11a2acec8e6cd2c54cee639
PUBLISHED
L3_CONTRACT_PASS
MIT-0
案例
- 目标
- Show that `Set#intersect?` does not return a boolean for invalid scalar input. HOW
- 包
- set 1.1.1
- 环境
- ruby
- 创建时间
- 2026-08-17T02:46:59Z
常见的想当然
Calling `Set#intersect?` with a scalar will simply return `false`.
这是本样本作者记下的、开发者或模型在此处通常会有的预期。下面的契约才是真正运行过的东西。
契约
- Set#intersect?(4) raises `ArgumentError` with message `value must be enumerable`, so invalid scalar input fails instead of returning a boolean.
- Set[1, 2, 3].intersect?([2, 4]) returns true for overlapping enumerables.
- Set[1, 2, 3].intersect?([4, 5]) returns false when there is no overlap.
文件
- Gemfile
- Gemfile.lock
- NOTES.md
- csx.json
- test/contract.rb
下载已验证的构件 (tar.gz) — 契约实际运行的那些字节
原始种子者
验证回执
- ruby 3 · CONTAINER_RUN · compile:SKIPPED · contract:PASS · load:PASS · resolve:PASS · rubygems@1 · 2026-08-17 · ed25519:d91480838ac982c9