示例
babel.transformFromAstSync returns null for the ast property by default; you must explicitly set ast: true in options to receive the transformed AST.
sha256:56562ad3e60744340664284a64b599eb18030a9389e6ac999d9e656c3a883f24
PUBLISHED
L3_CONTRACT_PASS
MIT-0
执行证据
分开显示声明环境和签名验证运行,明确样本的证明范围。
证据依据签名契约通过
验证回执1
验证级别L3_CONTRACT_PASS
声明的环境
- 执行上下文
- node
- 操作系统
- linux
- 架构
- x64
- 运行时
- node
- 语言
- node
- 包管理器
- npm
验证运行环境
- 执行上下文
- node 22
- 操作系统
- linux alpine · musl
- 架构
- x64
- 运行时
- node 22
- 语言
- javascript
- 包管理器
- npm
- 执行方式
- container · docker
CONTAINER_RUN · compile:SKIPPED · contract:PASS · load:PASS · resolve:PASS · node-typescript@1 · 2026-08-17
案例
- 目标
- babel.transformFromAstSync returns null for the ast property by default; you must explicitly set ast: true in options to receive the transformed AST. HOW
- 包
-
@babel/core 7.24.0
- 环境
- node
- 创建时间
- 2026-08-17T22:42:25Z
常见的想当然
babel.transformFromAstSync includes the processed AST in its return object by default, since it is an AST-focused API.
这是本样本作者记下的、开发者或模型在此处通常会有的预期。下面的契约才是真正运行过的东西。
契约
- babel.transformFromAstSync returns a null ast property by default to save memory, rather than returning the processed AST
- Passing ast: true is required to get the AST back in the result object
- The original AST is left completely unmutated because cloneInputAst defaults to true
- Setting cloneInputAst: false mutates the provided AST in place during traversal
- With cloneInputAst: false and ast: true, the returned ast property is the exact same object reference as the input AST
文件
- NOTES.md
- csx.json
- package-lock.json
- package.json
- scratch.js
- scratch2.js
- scratch3.js
- scratch4.js
- scratch5.js
- scratch6.js
- scratch7.js
- test/contract.mjs
下载源代码构件 (tar.gz)
原始种子者
csx-seed
验证回执
- node 22 · linux alpine/x64 · docker · CONTAINER_RUN · compile:SKIPPED · contract:PASS · load:PASS · resolve:PASS · node-typescript@1 · 2026-08-17 · ed25519:d91480838ac982c9