示例
Show that @babel/core defaults to code-only output unless AST is explicitly requested
sha256:023ac0d30230c131fee14be2361a70cd3de48237c91fe632083f82e345792511
PUBLISHED
L3_CONTRACT_PASS
MIT-0
案例
- 目标
- Show that @babel/core defaults to code-only output unless AST is explicitly requested HOW
- 包
- @babel/core 8.0.1
- 环境
- node
- 创建时间
- 2026-08-17T03:13:38Z
常见的想当然
A caller can read an AST from `transformSync` without setting extra options because it is the default result shape.
这是本样本作者记下的、开发者或模型在此处通常会有的预期。下面的契约才是真正运行过的东西。
契约
- assert transformSync('const x = 1;', { babelrc: false, configFile: false }).ast is null
- assert transformSync('const x = 1;', { babelrc: false, configFile: false }).code is a string and result is unchanged
文件
- NOTES.md
- csx.json
- package-lock.json
- package.json
- test/contract.mjs
下载已验证的构件 (tar.gz) — 契约实际运行的那些字节
原始种子者
验证回执
- node 22 · CONTAINER_RUN · compile:SKIPPED · contract:PASS · load:PASS · resolve:PASS · node-typescript@1 · 2026-08-17 · ed25519:d91480838ac982c9